If sinx is approximately 0.2588, what is the measurement of x to the nearest degree? Approximately, what is the cosine of the angle that is complementary to x?
Answer:
Part 1) \(x=15\°\)
Part 2) \(cos(75\°)=0.2588\)
Step-by-step explanation:
Part 1) we have
\(sin(x)=0.2588\)
using a calculator
\(x=sin^{-1}(0.2588)=15\°\)
Part 2)
we know that
If two angles are complementary
\(\alpha+\beta=90\°\) ------> complementary angles
then
\(cos(\alpha)=sin(\beta)\)
In this problem
we have
\(x=15\°\)
The angle complementary to x is equal to
\(90\°-15\°=75\°\)
so
\(cos(75\°)=sin(15\°)\)
therefore
\(cos(75\°)=0.2588\)
Answer:
The value of x is 15°,
The cosine of the angle that is complementary to x is 0.2588(approx)
Step-by-step explanation:
Given,
\(sin x = 0.2588\)
\(\implies x = sin^{-1}(0.2588)= 14.9988703055\approx 15^{\circ}\)
Hence, the value of x is 15°,
Now, the complementary angles are the two angles who give the sum of 90°,
⇒ Complementary angle of x = 90° - x = 90° - 15° = 75°
Thus, the cosine of the angle that is complementary to x,
cos(90-x) = cos 75° = 0.2588190451 ≈ 0.2588