Data:
\(E = 20 V\)
\(R_{1} = 65\Omega\)
\(R_{2} = 65\Omega\)
\(R_{3} = 65\Omega\)
\(R_{4} = 65\Omega\)
Now that we have all the values we need properly identified, simply calculate the equivalent total resistance of the circuit and the intensity of the total electric current using the Ohm's Law:
\(R_{T} = R_{1} + R_{2} + R_{3} + R_{4}\)
\(R_{T} = 65 + 65 + 65+ 65\)
\(R_{T} = 260\Omega\)
Like this:
\(I_{T} = \frac{E}{ R_{T} }\)
\(I_{T} = \frac{20}{ 260 }\)
\(I_{T} = 0,076923076...\)
\(\boxed{\boxed{I_{T} \approx 0,07A}}\)
Answer:
The intensity of the total electric current
\(\boxed{\boxed{I_{T} \approx 0,07A}}\)
P.S:. Since the association is in series, the current of 0.07A is the same for all resistors.
