In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O
Answer : The number of moles of \(Ca(OH)_2\) required are, 0.6 mole.
Explanation : Given,
Moles of HI = 1.2 moles
The given balanced chemical reaction is,
\(2HI+Ca(OH)_2\rightarrow CaI_2+2H_2O\)
From the balanced chemical reaction, we conclude that
As, 2 moles of \(HI\) react with 1 mole of \(Ca(OH)_2\)
So, 1.2 moles of \(HI\) react with \(\frac{1.2}{2}=0.6\) mole of \(Ca(OH)_2\)
Therefore, the number of moles of \(Ca(OH)_2\) required are, 0.6 mole.