\(a_5=ra_4=r^2a_3=r^3a_2=r^4a_1\iff150.06=16r^4\implies r\approx\pm1.75\)
Regardless of the sign of the common ratio, then, you will have
\(a_{17}=r^{16}a_1\approx16(\pm1.75)^{16}\approx123802.31\)
The actual term would be closer to \(123794\) if you didn't have to round.
