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16-01-2017
Physics

Answered

The temperature at 8:00

a.m. was –6°

f. by 4:00 p.m. the temperature was 17°

f. what was the change in temperature from 8:00

a.m. to 4:00 p.m.?

A–23°f
B–11°f
C11°f
D23°f

Verified Answer :

Anonymous Anonymous

16-01-2017

Change in temperature = final temperature - Initial temperature
Δt = t₂ - t₁
Δt = 17 - (-6)
Δt = 17 + 6 = 23 f

In short, Your Answer would be Option D

Hope this helps!

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