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kelseygadd2 kelseygadd2
  • 15-01-2017
  • Mathematics
Answered

use Gauss approach to find the sum of the following numbers

1+2+3+4+...+98

Verified Answer :

Newtion Newtion
  • 15-01-2017

\(\displaystyle 1+2+3+4+...+n= \frac{n(n+1)}{2}\)

According to Gauss's formula, we can get:

\(\displaystyle 1+2+3+4+...+98= \frac{98(98+1)}{2}=49\cdot 99=4851\)

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