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holo4 holo4
  • 15-01-2017
  • Chemistry
Answered

calculate the concentration of the following solution in mol/dm3 0.1 moles of NaCl in 200 cm3

Verified Answer :

AbhiGhost
AbhiGhost AbhiGhost
  • 15-01-2017

1 \(cm ^{3}\) = 0.001 \(dm ^{3}\). Therefore 200 \(cm ^{3}\) = 0.2 \(dm ^{3}\). Molarity = \(\frac{number of moles of NaCl}{volume of the solution} = \frac{0.1}{0.2} = 0.5 mol/dm^{3}\). Hope this helps.

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