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Consider the following chemical reaction:


4HCl + MnO2 → MnCl2 + 2H2O + Cl2 .


When 0.268 mol of HCl reacts stoichiometrically with MnO2, how many grams of Cl2 is produced?

Verified Answer :

arthurpdc

According to the equation, the ratio of \(HC\ell\) to \(C\ell_2\) is \(4:1\). Then:

\(\dfrac{n_{HC\ell}}{n_{C\ell_2}}=\dfrac{4}{1}\Longrightarrow\dfrac{0.268}{n_{C\ell_2}}=\dfrac{4}{1}\Longrightarrow n_{C\ell_2}=\dfrac{0.268}{4}\iff n_{C\ell_2}=0.067~mol\)

Now we can calculate the mass of \(C\ell_2\) formed.

\(m_{C\ell_2}=n_{C\ell_2}\cdot MM_{C\ell_2}\Longrightarrow m_{C\ell_2}=0.067\cdot(2\cdot35.5)\Longrightarrow\\\\ m_{C\ell_2}=0.067\cdot71\Longrightarrow\boxed{m_{C\ell_2}=4.757~g}\)

AbhiGhost

Here's your solution. Hope it helps.

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