we can't facotr this
for
ax^2+bx+c=0
x=\(\frac{-b+/- \sqrt{b^2-4ac} }{2a}\)
1x^2+6x+7
x=\(\frac{-6+/- \sqrt{6^2-4(1)(7)} }{2(1)}\)
x=\(\frac{-6+/- \sqrt{36-28} }{2}\)
x=\(\frac{-6+/- \sqrt{8} }{2}\)
x=\(\frac{-6+/- 4\sqrt{2} }{2}\)
x=\(-3+/- 2\sqrt{2}\)
x=\(-3+ 2\sqrt{2}\) and x=\(-3- 2\sqrt{2}\)
