Answered

The first term of a geometric series is 3, and the sum of the first term and the second term is 15. What is the sum of the first six terms?

A1,023

B3,906

C4,095

D11,718

Verified Answer :

Sum of n terms in a geometric progression is given by Sn = a1 (1 - r^n) / (1 -r)

3( 1 - 4^6) / (1-4)

= 4,095

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