How do you solve 6 7/8 + 1 2/8 =
\(6\frac{7}{8}+1\frac{2}{8}=(6+\frac{7}{8})+(1+\frac{2}{8})=(6+1)+\left(\frac{7}{8}+\frac{2}{8}\right)\\\\=7+\frac{7+2}{8}=7+\frac{9}{8}=7+\frac{8+1}{8}=7+\frac{8}{8}+\frac{1}{8}=7+1+\frac{1}{8}\\\center{\boxed{\boxed{=8\frac{1}{8}}}\)