Answered

Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.


6√3 in.²

9 in.²

18 in.²

Verified Answer :

ferretgirl02

area of a triangle = (b x h) /2
(2√3 × 3√3 )/2=
(2×3√3×3)/2 =
(6√9)/2 =
(6×3)/2 =
18/2 =
9 in²
Hope this helps

Answer:

B. 9 inch²

Step-by-step explanation:

We are given that,

Base of the triangle = \(2\sqrt{3}\) inches

Height of the triangle = \(3\sqrt{3}\) inches

Now, Area of the triangle = \(\frac{1}{2}(Base\times Height)\)

i.e. Area of the triangle = \(\frac{1}{2}(2\sqrt{3}\times 3\sqrt{3})\)

i.e. Area of the triangle = \(\frac{1}{2}(6\times 3)\)

i.e. Area of the triangle = \(\frac{18}{2}\)

i.e. Area of the triangle = 9 inch²

Thus, the area of the triangle is 9 inch².

So, option B is correct.

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