Answered

The legs of a right triangle measure 5√2 cm and 4√2 cm. Find the area.


10√2 sq. cm

20 sq. cm

20√2 sq. cm

Verified Answer :

khankareem

The answer is 20 sq.cm

Answer: The answer is (b) 20 sq. cm.

Step-by-step explanation:  As given in the question and shown in the attached figure, ABC is a right-angled triangle with ∠ABC = 90°, the legs AB = 4√2 cm and BC = 5√2 cm.

We are to calculate the area of ΔABC.

Since AB is perpendicular to BC, so AB will be height and BC will be the base of the triangle.

Therefore, area of ΔABC is

\(a=\dfrac{1}{2}\times AB\times BC=\dfrac{1}{2}\times 4\sqrt 2\times 5\sqrt 2=20~\textup{sq. cm.}\)

Thus, the correct option is (b) 20 sq. cm.

View image ColinJacobus

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