a disk with a radius of 0.1 m is spinning about its center with a constant angular speed of 10 rad/sec. What are the speed and magnitude of the acceleration of a bug clinging to the rim of the disk?

Verified Answer :

The speed of the bug at the rim of the circular disk is \(\boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}}}\) and the acceleration of the bug is \(\boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern- ulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}\).


Further Explanation:

Given:


The angular velocity of the disk is \(10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}}\).

The radius of the circular disk is \(0.1\,{\text{m}}\).


Concept:


The linear speed of the bug present at the rim of the circular disk is given by.

\(v = r \times \omega\)


Here, \(v\) is the linear speed,\(r\) is the radius of the disk and \(\omega\) is the angular speed of the disk.


Substitute \(0.1\,{\text{m}}\) for \(r\) and \(10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}}\) for \(\omega\) in above expression.

\(\begin{aligned}v &= 0.1\,{\text{m}} \times 10\,{{{\text{rad}}} \mathord{\left/{\vphantom {{{\text{rad}}} {\text{s}}}} \right. \kern- ulldelimiterspace} {\text{s}}} \\&= 1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}} \\\end{aligned}\)


The magnitude of the centripetal acceleration of the bug cling to the rim of the disk is given as.

\({a_c} = \dfrac{{{v^2}}}{r}\)  


Substitute \(1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}}\) for \(v\) and \(0.1\,{\text{m}}\) for \(r\) in above equation.

\(\begin{aligned}a_c&=\dfrac{(1\text{m/s})^2}{0.1\text{m}}\\&=\frac{1}{0.1}\text{m/s}^2\\&=10\,\text{m/s}^2\end{aligned}\)  


Thus, the speed of the bug at the rim of the circular disk is \(\boxed{1\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {\text{s}}}} \right.\kern- ulldelimiterspace} {\text{s}}}}\) and the acceleration of the bug is \(\boxed{10\,{{\text{m}} \mathord{\left/{\vphantom {{\text{m}} {{{\text{s}}^{\text{2}}}}}} \right.\kern- ulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}\).


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Answer Details:

Grade: College

Chapter: Uniform Circular motion

Subject: Physics


Keywords:  Circular disk, circular motion, angular speed, linear speed, bug clinging, rim of the disk, acceleration, magnitude, constant, rad/s.