A child on a spinning playground ride is 0.36 m from the center of the ride. the centripetal force on the child is 19 n. what is the mass of the child if the child has a tangential speed of 0.54 m/s?3.7 kg13 kg23 kg79 kg
A centripetal force is a force that makes a body follow a curved path. Its direction is always orthogonal to the motion of the body. It has formula given as:
F = m (v^2 / R)
19 = m (0.54^2 / 0.36)
m = 23.46 kg
Hope this answers the question. Have a nice day.
Answer:
\(m = 23.45 kg\)
Explanation:
As we know that the centripetal force in uniform circular motion is given as
\(F = \frac{mv^2}{R}\)
now we have
\(F = 19 N\)
v = 0.54 m/s
R = 0.36 m
so we will have
\(F = \frac{mv^2}{R}\)
\(19 = \frac{m \times 0.54^2}{0.36}\)
\(19 = m(0.81)\)
\(m = 23.45 kg\)