Molar mass of chloroform (CHCl3)
C = 1 12 = 12 a.m.u
H = 1 1 = 1 a.m.u
Cl = 3 * 35.5 = 106.5 a.m.u
Molar Mass (CHCl3) = 12 + 1 + 106.5 = 119.5 g / mol
Knowing that:
The value of Avogadro's constant corresponds to approximately \(6,02*10^{23}\) molecules, if chloroform contains \(1,00 * 10^{12}\) molecules.
We have:
\(1,00 * 10^{12} * 6,02 * 10^{23} = 6,02 * 10 ^ {35} molecules\)
Now, how many grams are there in the chloroform molecule?
grams -------- molecules
119,5 → \(6,02 * 10^{23}\)
x → \(6,02 * 10^{35}\)
\(6,02 * 10 ^ {23} * x = 119,5 * 6,02 * 10 ^{35}\)
\(6,02 * 10 ^ {23}x = 719,39 * 10^{35}\)
\(x = \frac{719,39}{6,02}*10^{35-23}\)
\(\boxed{x = 119,5*10^{12}grams}\)
