lindseyknapp
Answered

A piece of metal (mass = 17.676 g) is placed in 11.00 mL of chloroform (d = 1.498 g/mL) in a 25-mL graduated cylinder. The chloroform level increases to 15.46 mL. The best value for density of this metal from these data is

Verified Answer :

britt3606

Volume = 15.46-11.00mL = 4.46mL

Density = mass/vol = 18.592g/4.46mL = 4.1686g/mL = 4.1686g/cm^3

Answer : The density of metal will be 3.963 g/mL

Explanation : Given,

Mass of metal = 17.676 g

Initial volume of chloroform = 11.00 mL

Final volume of chloroform = 15.46 mL

First we have to calculate the volume of metal.

Volume of metal = Final volume of chloroform - Initial volume of chloroform

Volume of metal = 15.46 - 11.00 = 4.46 mL

Now we have to calculate the density of metal.

\(\text{Density of metal}=\frac{\text{Mass of metal}}{\text{Volume of metal}}\)

\(\text{Density of metal}=\frac{17.676g}{4.46mL}=3.963g/mL\)

Therefore, the density of metal will be 3.963 g/mL

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