Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form
slope = (10 -5)/(2+3) = 5/5=1
y = mx + b
5 = 1(-3) + b
b =8
so equation y = x +8
answer: y = x + 8(first choice)
Answer:
The slope-intercept form is \(y=x+8\)
Step-by-step explanation:
Given points are (-3, 5) and (2,10). Now, we have to find the equation of the line that passes through these points in slope-intercept form.
Equation of line passing through the point (x', y') can be written as
\(y-y'=m(x-x')\) where m is \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)
Hence, the equation can be written as \((y-5)=\frac{10-5}{2-(-3)}(x-(-3))\)
⇒ \(y-5=\frac{5}{5}(x+3)\)
⇒ \(y=x+3+5\)
⇒\(y=x+8\)
which is slope-intercept form where slope is 1 and intercept is 8 by comparing with y=mx+c