Answered

20%

of Desiree's math test problems consisted of word problems. 30%

of Everett's math test problems consisted of word problems. Which statement must be true?



If they completed the same number of problems, Everett had 10

more word problems than Desiree.



Desiree had less word problems than Everett did.



If they both completed 20

problems, then Everett had 1

more word problem than Desiree.



If Everett completed 10

problems and Desiree completed 15

problems, then they both completed the same number of word problems.

Verified Answer :

measd

The final statement is correct.

\(30\% * 10 = 3 ewline 20\% * 15 = 5\)

Number of word problem in Desiree's math test = 20 %

Number of word problem in Desiree's math test = 30 %

Keep in Mind→→→M% of N = \(\frac{MN}{100}\)

Starting from

1. Option 1:

Let number of problems in maths test of Everett and Desiree = x

20 % of x = \(\frac{20 x}{100}\)

30 % of x =  \(\frac{30 x}{100}\)

Suppose ,Only for, x= 100, Everett had 10
,more word problems than Desiree.

But for other values of x, this statement is not true.

→→Incorrect Option

2. Option 2→→Desiree had less word problems than Everett did.

The Statement would be true , if Number of word problem solved by Everett and Desiree are same.

But ,If number of word problem solved by Everett and Desiree are different, then this statement is incorrect.For example, considering number of word problem solved by Desiree= 200, and number of word problem solved by Everett = 100

→→→Incorrect Option

3. Option 3:

→→If they both completed 20
problems, then Everett had 1
,more word problem than Desiree.

Desiree=20 % of 20 = 4

Everett =30 % of 20 = 6

→→→→Incorrect statement.

Option 4:

→If Everett completed 10,
problems and Desiree completed 15

problems, then they both completed the same number of word problems.

→→Everett = 30% of 10=3

→→Desiree = 20% of 15 = 3

Correct Option

Related Questions