A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt?
Answer : The kinetic energy of the box is, 80 J
Explanation :
The formula used for kinetic energy is:
\(K.E=\frac{1}{2}mv^2\)
where,
K.E = kinetic energy = ?
m = mass = 40 kg
v = velocity = 2 m/s
Now put all the given values in the above formula, we get the kinetic energy of the box while it is on the conveyor belt.
\(K.E=\frac{1}{2}mv^2\)
\(K.E=\frac{1}{2}\times (40kg)\times (2m/s)^2\)
\(K.E=80kg.m^2/s^2=80J\)
Thus, the kinetic energy of the box is, 80 J
The kinetic energy of the box on the conveyer belt is 80 J.
Given that the mass m of the box is 40 kg and velocity v is 2 m/s.
The kinetic energy of the box can be calculated as given below.
\(KE = \dfrac {1}{2} mv^2\)
Substituting the values of mass and velocity.
\(KE = \dfrac {1}{2}\times 40\times 2^2\)
\(KE = 80 \;\rm J\)
Hence we can conclude that the kinetic energy of the box is 80 J.
To know more about kinetic energy, follow the link given below.
https://brainly.com/question/999862.