c8laurarmilymilyn c8laurarmilymilyn

13-01-2017
Chemistry

Answered

Suppose you had 10 mol of NaCl and you dissolved it in exactly 3.00 kg of pure water (the solvent). What would be the molality of the solution in mol/kg?

Verified Answer :

AbhiGhost AbhiGhost

13-01-2017

Molality = number of moles of solute/mass of solvent in kg = 10/3 = 3.34 mol/kg.

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