Verified Answer :
delta U = Q - W and W in this case = P delta V. Use standard pressure, change in V is given and heat added is given.
V=22.4 dm^3,
T = 273.15 K (0 °C)
p=101325 Pa
V2 = 32.4 dm^3
p = const.
V1 / T1 = V2 / T2
T2 = T1 V2 / V1
= 273.15 K 32.4 dm^3 /22.4 dm^3
= 395.092 K (121.9 °C)
Internal energy: E(i) = NkT,
where N = 610^23 k = 1.3810^-23
E(i1) = 610^23 1.3810^-23 273.15 = 2261.682 J
E(i2) = 610^23 1.3810^-23 395.092 = 3271.362 J
delta E(i) = 1009.68 J
What is internal energy ?
"Internal energy, in thermodynamics, the property or state function that defines the energy of a substance in the absence of effects due to capillarity and external electric, magnetic, and other fields."
What is pressure ?
"Pressure is defined as a measure of the force applied over a unit area. Pressure is often expressed in units of Pascals (Pa), newtons per square meter (N/m2 or kg/m·s2), or pounds per square inch. Other units include the atmosphere (atm), torr, bar, and meters sea water (msw)."
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