Verified Answer :
a= 50/8 m/s^2
vf=at=50/8 5= 250/8 m/s at t=5sec
time to get to 50m/s
50=50/8t or t=8 seconds
distance=1/2 a t^2=1/2 50/8 64
distance= 400 m check that.
Answer : Its acceleration is, \(6.25m/s^2\)
The velocity after 5 s is, 31.25 m/s
The distance traveled by the time it reaches 50 m/s is, 200 m
Solution :
First we have to calculate the acceleration.
Formula used : \(a=\frac{\Delat v}{t}\)
where,
a = acceleration
v = change in velocity = 50 - 0 = 50 m/s
t = time = 8 s
Now put all he given values in the above formula, we get
\(a=\frac{50m/s}{8s}=6.25m/s^2\)
Therefore, its acceleration is, \(6.25m/s^2\)
Now we have to calculate the velocity after 5 second.
Formula used : \(v=u+at\)
where,
v = final velocity
u = initial velocity = 0 m/s
a = acceleration = \(6.25m/s^2\)
t = time = 5 s
Now put all the given values in the above formula, we get
\(v=0m/s+(6.25m/s^2)\times (5s)=31.25m/s\)
Therefore, the velocity after 5 s is, 31.25 m/s
Now we have to calculate the distance traveled by the time it reaches 50 m/s.
Formula used : \(v^2-u^2=2as\)
where,
s = distance traveled
Now put all the given values in the above formula, we get
\((50m/s)^2-(0m/s)^2=2\times (6.25m/s^2)\times s\)
\(s=200m\)
Therefore, the distance traveled by the time it reaches 50 m/s is, 200 m