How many grams of chlorine gas must react to give 4.82g of BiCl3?

2Bi(s)+3Cl2(

g.→2BiCl3(s) My answer was wrong/please review and tell me where I went wrong.

4.82g BiCl31mol BiCl3/215.33g BiCl33 mol Cl2/2 mol Bicl3* 70.9g Cl2/1 mol Cl2=6.50 g Cl2