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In physics, if a moving object has a starting position at s0, an initial velocity of v0, and a constant acceleration a, then the position S at any time t > 0 is given by:

S = 1/2 at^2 + v0*t + s0. Solve for the acceleration, a, in terms of the other variables.

Verified Answer :

apologiabiology

S=1/2at^2+v₀t+s₀
minus (v₀t+s₀) from both sides
S-v₀t-s₀=1/2at²
times 2 both sides
2(S-v₀t-s₀)=at²
divide both sides by t²
\(\frac{2(s-v_0t-s_0)}{t^2} =a\)

Lanuel

The formula for acceleration (a) in terms of the other variables is \(a = \frac{2(S - v_0t -s_0)}{t^2}\).

Given the following data:

  • Starting position = \(s_o\)
  • Initial velocity = \(v_o\)
  • Constant acceleration = a

To solve for the acceleration (a) in terms of the other variables:

In this exercise, you're required to make acceleration (a) the subject of formula in the given mathematical expression. Thus, we would solve for acceleration (a) in terms of the other variables as follows;

The subject of formula.

First of all, we would rearrange the given equation:

\(S = \frac{1}{2} at^2 + v_0t + s_0\\ \\ \frac{1}{2} at^2 = S - v_0t -s_0\)

Next, multiply both sides by 2 and divide by \(t^2\):

\(a = \frac{2(S - v_0t -s_0)}{t^2}\)

Read more on subject of formula here: https://brainly.com/question/11000305

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