Answer:
238 feet.
Step-by-step explanation:
Refer the attached figure .
An observer is standing in a lighthouse 96 feet above the level of the water.i.e AC = 96 feet
The angle of depression of a buoy is 22° i.e. ∠ABC = 22°
Now we are required to find the horizontal distance between the observer and the buoy i.e. BC
Now, use trigonometric ratio.
\(tan\theta = \frac{Perpendicular}{Base}\)
\(tan22^{circ} = \frac{96}{BC}\)
\(0.404= \frac{96}{BC}\)
\(BC= \frac{96}{0.404}\)
\(BC= 237.62\)
Thus the horizontal distance between the observer and the buoy is 237.62≈238 feet.
