\(4x-5y=19 \\
y=8x-11 \\ \\
\hbox{substitute 8x-11 for y in the 1st equation and solve for x:} \\
4x-5(8x-11)=19 \\
4x-40x+55=19 \\
4x-40x=19-55 \\
-36x=-36 \\
x=\frac{-36}{-36} \\
x=1 \\ \\
\hbox{substitute 1 for x in one of the equations and solve for y:} \\
y=8 \times 1-11 \\
y=8-11 \\
y=-3 \\ \\
(x,y)=(1,-3)\)
