Answer:
\((x-4)^{2}+(y-1)^{2} =4\)
Step-by-step explanation:
we know that
The equation of a circle in center radius form is equal to
\((x-h)^{2}+(y-k)^{2} =r^{2}\)
where
(h,k) is the center of the circle
r is the radius of the circle
In this problem we have
\((h,k)=(4,1)\)
\(r=2\ units\)
substitute
\((x-4)^{2}+(y-1)^{2} =2^{2}\)
\((x-4)^{2}+(y-1)^{2} =4\)
