Answer:
\(\frac{1}{4}(-3n+\frac{3}{2})\) is \(\frac{-6n+3}{8}\)
Step-by-step explanation:
Given that: \(\frac{1}{4}(-3n+\frac{3}{2})\) ......[1]
The distributive property says that:
\(a.(b+c)=a.b+a.c\)
Apply distributive property on [1] we have;
\(=\frac{1}{4}.(-3n)+\frac{1}{4}.\frac{3}{2}\)
Simplify:
\(=\frac{-3n}{4}+\frac{3}{8}\)
\(=\frac{-6n+3}{8}\)
Therefore, the expression that shows the result of applying the distributive property to \(\frac{1}{4}(-3n+\frac{3}{2})\) is \(\frac{-6n+3}{8}\)
