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Given that the small piston has a radius of 0.0330 meters^2 and the large piston has a radius of 4.00 meters^2.

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AWhat force will the large piston provide if the small piston is pushed down with a force of 17.0 N?.

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BIf the small piston is slowly depressed a distance of y1 = 0.300 m, by how much will the large piston rise?

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CHow much work was done in pushing down the small piston? How much work was done by the large piston?

Verified Answer :

MissPhiladelphia

so the problem is about pressureP = F / awhere P is the pressureF is the force applieda is the area
a.) F1 / a1 = F2 / a2F1 / 4 m^2 = 17 N /  0.033 m^2F1 = ( 4 m^2 ) 17 N /  0.033 m^2F1 = 2060.6 N
b.) firts solve the volume of the small pistonV = AhV = 0.300 m ( 0.033 m^2)V = 0.0099 m^3so the Volume are equal in both
0.0099 = 4hh = 0.002475 m
c. w = Fdwork small psiton = 17N(0.3m) = 5.1 jwork big piston = 2060.6N(0.002475m) = 5.1 j

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