Answered

A 2.1 × 103

kg car accelerates from rest under

the action of two forces. One is a forward

force of 1141 N provided by traction between

the wheels and the road. The other is a 911 N

resistive force due to various frictional forces.

How far must the car travel for its speed to

reach 2.9 m/s?

Answer in units of m.

Verified Answer :

MissPhiladelphia

First solve the acceleration of the car using the formula


Fnet = ma

Where Fnet is the net force acting on the body

M of the object

A is the acceleration


( 1141 – 911) = (2.1 x10^3) a


a = 0.1095 m/s2



a = v/t


0.1095 = 2.9 /t


t = 26.4783 s



d = vt


d = ( 2.9 m/s) ( 26.4783 s)

d = 76.7870 m