How many grams of N2 must react to form 1.7 grams of ammonia, NH3?
Answer:
The correct answer is 1.4g of nitrogen.
Explanation:
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The reaction to
creating ammonia from nitrogen is:
N2 (g) + 3H2 ---> 2NH3 (g)
NH3 mass = 1.7 g
N2 = 28g / mol
NH3 = 17g / mol
each one mole of nitrogen we obtain two moles of ammonia, then:
mass N2 = 1.7g * (28g / mol / 17g / mol) = 1.4g
We conclude that the correct answer is 1.4g of nitrogen.