Solve the system.


{j+k=3

{j−k=7


Use the substitution method.


A.The solution is (5, −2).


B.There is no solution.


C.There are an infinite number of solutions.


D.The solution is (8, 1).

Verified Answer :

the answer A.the solution is (5,-2) definitely works because 5+-2=3 and 5--2=7 not sure if there's infinite number of solutions tho

i know this is late but this man is right i double checked with k12 and its (5, -2)