\(2x^4+5x^3+38x^2+125x-300=0\\\\2x^4+5x^3-12x^2+50x^2+125x-300=0\\\\x^2(2x^2+5x-12)+25(2x^2+5x-12)+0\\\\(2x^2+5x-12)(x^2+25)=0\\\Updownarrow\\1^o\ 2x^2+5x-12=0\ \vee\ 2^o\ x^2+25=0\\\\\\1^o\ \Delta=5^2-4\cdot2\cdot(-12)=25+96=121\\\\\sqrt\Delta=\sqrt{121}=11\\\\x_1=\frac{-5-11}{2\cdot2}=\frac{-16}{4}=-4;\ x_2=\frac{-5+11}{2\cdot2}=\frac{6}{4}=\frac{3}{2}\\\\\\2^o\ x^2=-25-false\\\\\\Answer:x=-4\ or\ x=\frac{3}{2}\)