Verified Answer :

apologiabiology

so listen to this logic
lets say you have 3 numbers, m,a,x where they are all positivie
m>a>x
therefor
m^2>a>2>x^2
if m and a and x are square roots, therefor we can reverse the square root
confusing sorry

square 5 and 6
5^2=25
6^2=36

the number betwe 25 and 36

that would be 32

answer is √32

goes like this
5^2<32<6^2
sqrt both sides
5<√32<6

answer is √32

Answer:

\(\sqrt{32}\)

Step-by-step explanation:

expressions has a value between 5 and 6.

First we take perfect square numbers

WE know \(\sqrt{25} = 5\)

\(\sqrt{36} = 6\)

We need to find a value between 5  and 6

That means we need to find a value between \(\sqrt{25} \  and \ \sqrt{36}\)

\(\sqrt{17}\) does not lie between \(\sqrt{25} \ and \ \sqrt{36}\)

\(\sqrt{32}\)  lie between \(\sqrt{25} \ and \ \sqrt{36}\)

\(\sqrt{60}\) does not lie between \(\sqrt{25} \ and \ \sqrt{36}\)

\(\sqrt{1125}\) does not lie between \(\sqrt{25} \ and \ \sqrt{36}\)

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