Answer : The correct option is, 112 ml
Solution : Given,
Mass of \(SO_2\) = 0.640 g
Molar mass of \(SO_2\) = 64 g/mole
First we have to calculate the moles of \(SO_2\).
\(\text{Moles of }SO_2=\frac{\text{Mass of }SO_2}{\text{Molar mass of }SO_2}=\frac{0.640g}{64g/mole}=0.01moles\)
Now we have to calculate the moles of oxygen gas.
The balanced chemical reaction will be,
\(2SO_2+O_2\rightarrow 2SO_3\)
From the reaction, we conclude that
As, 2 moles of \(SO_2\) react with 1 mole of \(O_2\) gas
So, 0.01 moles of \(SO_2\) react with \(\frac{0.01}{2}=5\times 10^{-3}\) mole of \(O_2\) gas
Now we have to calculate the volume of oxygen gas.
As, 1 mole of oxygen gas contains 22400 ml volume of oxygen gas
So, \(5\times 10^{-3}\) mole of oxygen gas contains \(22400ml\times (5\times 10^{-3})=112ml\) volume of oxygen gas
Therefore, the volume of oxygen gas is, 112 ml
