\(\left[\begin{array}{ccc}6&3&1\\8&4&1\
&-2&1\end{array}\right]=0\)
\(6*4*1+3*n*1+8*(-2)*1-1*4*n-6*(-2)*1-8*3*1=0\)
\(24+3n-16-4n+12-24=0\)
\(3n-4n+\diagup\!\!\!\!\!24-16+12-\diagup\!\!\!\!\!24=0\)
\(3n-4n-16+12=0\)
\(-n-4=0\)
Keep the number on the left incognito and Put the number on the right without incognito by changing the sign.
\(-n =4\) simplify by (-1)
\(\boxed{n = - 4}\)
Answer:
\(\boxed{n = -4}\)
