Verified Answer :

This answer is A. 
Basically, the parabola opens downward so you know that the equation has a negative in the front... 

Answer:

Thus, (a) is correct.

\(y=-(x+1)^2+3\) is the equation of the given graph

Step-by-step explanation:

Given a graph with vertex (-1 , 3)

We have to determine the equation of the graph and choose from the given options.

Since, the graph represents a quadratic equation.

The general form of representing a quadratic equation is \(y=a(x-h)^2+k\) , where (h,k) is the vertex. a determine whether the graph open ups or down if it is positive then it open upward and vice versa.

For the given graph, vertex (-1 , 3)

Substitute h = -1 and k = 3  in \(y=a(x-h)^2+k\) we get,

\(y=a(x+1)^2+3\)

Also the graph opens down ward so a has to be negative,

So \(y=-(x+1)^2+3\)

Thus, Option (a) is correct.