Verified Answer :

An arithmetic sequence has the recursive structure

\(a_n=a_{n-1}+d\)

and can be solved explicitly for the \(n\) term, \(a_n\), in terms of the first term of the sequence \(a_1\).

\(a_n=a_{n-1}+d\)
\(\implies~a_n=a_{n-2}+2d\)
\(\implies~a_n=a_{n-3}+3d\)
\(\implies\cdots\implies a_n=a_1+(n-1)d\)

You know the 100th term of the sequence is \(a_{100}=1000\) and that the common difference between terms is \(d=5\), which means you have enough information to find the first term:

\(a_{100}=a_1+(100-1)\times5\implies1000=a_1+99\times5\implies a_1=505\)

The nth term of an arithmetic sequence = a + (n - 1)d

a = 1st term = ?        n =nth term = 100.  d = common difference = 5

a₁₀₀ = a + (100 - 1)d

a₁₀₀ = a + 99d = 1000

a + 99d = 1000

a + 99*5 = 1000

a + 495 = 1000

a = 1000 - 495

a = 505

So the first term a, is the same as a₁ = 505

I hope this helped.