For the following arithmetic sequence, if d=5 and a_100=1000,what is a_1 ?
An arithmetic sequence has the recursive structure
\(a_n=a_{n-1}+d\)
and can be solved explicitly for the \(n\) term, \(a_n\), in terms of the first term of the sequence \(a_1\).
\(a_n=a_{n-1}+d\)
\(\implies~a_n=a_{n-2}+2d\)
\(\implies~a_n=a_{n-3}+3d\)
\(\implies\cdots\implies a_n=a_1+(n-1)d\)
You know the 100th term of the sequence is \(a_{100}=1000\) and that the common difference between terms is \(d=5\), which means you have enough information to find the first term:
\(a_{100}=a_1+(100-1)\times5\implies1000=a_1+99\times5\implies a_1=505\)
The nth term of an arithmetic sequence = a + (n - 1)d
a = 1st term = ? n =nth term = 100. d = common difference = 5
a₁₀₀ = a + (100 - 1)d
a₁₀₀ = a + 99d = 1000
a + 99d = 1000
a + 99*5 = 1000
a + 495 = 1000
a = 1000 - 495
a = 505
So the first term a, is the same as a₁ = 505
I hope this helped.