Crystallauritsen Crystallauritsen

10-01-2017
Physics

Answered

A railroad car of 2000 kg coasting at 3.0 m/s overtakes and locks with an identical car coasting on the same track in the same direction at 2.0 m/s. What is the speed of the cars after they lock together?

Verified Answer :

LuismiSF LuismiSF

10-01-2017

The key is in "they lock together". This tells you this is a complete inelastic collision and therefore you can use the formula:
m1v1+m2v2=v(m1+m2)
Plug in numbers:
20003+20002=v(2000+2000)
so v=2 m/s, obviously in the same direction of motion in which they were both moving.

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