if 3x^2-2x+7=0 then (x-1/3)^2=
3x^2−2x+7=03x^2−2x+1/3+7−1/3=03(x^2−2x/3+1/9)+7−1/3=03(x−1/3)^2+(21−1)/3=03(x−1/3)^2=−20/3(x−1/3)^2=−20/9