CharlieSheen
Answered

What is wrong with my code...



def bigger(b,c):

if b > c:

return b

else:

return c

if b is returned, then b >c

if c is returned, then c > b

def biggest(a,b,c):

return bigger(a,bigger(b,c))



def median(a,b,c):

if biggest(a,b,c) == c and bigger(a,b) ==a:

c > b and c > a

a > b

return a

elif biggest(a,b,c) == c and bigger(a,b)==b:


return b

else:

return c

Verified Answer :

I'm not sure of the problem that you had in the first place, but I can point out that in your "bigger" method, if a number is greater than one then it is bigger, however the else statement says that the number can also be equal[==] to the second argument, so for example bigger(1,1) it would check if 1 > 1 and return false, so it will return that b[the second 1] is bigger! Hope this helps :D

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