A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?

Verified Answer :

25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N

Answer:

The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.

Explanation:

Given that,

Force = 1500 N

Area \(A= 25 m^2\)

We need to find the force to be applied on a 0.8 m2 piston to lift the crate

Using formula of pressure

The pressure is the force upon area.

\(P =\dfrac{F}{A}\)

Where, F = force

A = area

Pressure for first force,

\(P =\dfrac{F}{A}\)

\(P =\dfrac{1500}{25}\)...(I)

Pressure for second force,

\(P =\dfrac{F}{0.8}\)...(II)

Equate the equations (I) and (II)

\(\dfrac{1500}{25}=\dfrac{F}{0.8}\)

\(F=\dfrac{1500\times0.8}{25}\)

\(F=48\ N\)

Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.