A Heavy crate applied a force of 1500 N on a 25m2 piston. What force needs to be applied on a 0.8m2 piston to lift the crate?
25/1500 is equal to 0.8/x
0.8*1500 is equal to 1200
1200/25 is equal to 48 N
Answer:
The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.
Explanation:
Given that,
Force = 1500 N
Area \(A= 25 m^2\)
We need to find the force to be applied on a 0.8 m2 piston to lift the crate
Using formula of pressure
The pressure is the force upon area.
\(P =\dfrac{F}{A}\)
Where, F = force
A = area
Pressure for first force,
\(P =\dfrac{F}{A}\)
\(P =\dfrac{1500}{25}\)...(I)
Pressure for second force,
\(P =\dfrac{F}{0.8}\)...(II)
Equate the equations (I) and (II)
\(\dfrac{1500}{25}=\dfrac{F}{0.8}\)
\(F=\dfrac{1500\times0.8}{25}\)
\(F=48\ N\)
Hence, The force need to be applied on a 0.8 m² piston to lift the crate is 48 N.