First and second place in a contest use a ratio to share a cash prize. When first place pays $100 , second place pays $60. How much does first place pay when second place pays $36? Complete the ratio table to solve the problem
Answer:
\(\$60\)
Step-by-step explanation:
Using a proportion
Let
x-------> the pay of the first place when the second place pays \(\$36\)
\(\frac{\$100}{\$60}=\frac{x}{\$36}\\ \\x=36*100/60\\ \\x=\$60\)
The amount paid for first place pay when second place pays $36 is $60.
Given
First and second place in a contest uses a ratio to share a cash prize.
When first place pays $100, second place pays $60.
The quantitative relation between two amounts shows the number of times one value contains or is contained within the other:
Let, x be the amount paid in the first place when the second-place pays.
Then,
\(\rm \dfrac{100}{60} = \dfrac{x}{36}\\\\100 \times 36 = x \times 60\\\\3600 = 60x\\\\x = \dfrac{3600}{60}\\\\x=60\)
Hence, the amount paid for first place pay when second place pays $36 is $60.
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