Verified Answer :

LammettHash

\(\log_b\sqrt{\dfrac{13}{73}}=\dfrac12\log_b\dfrac{13}{73}=\dfrac{\log_b13-\log_b73}2\)

Answer:

\(\frac{log_b{13}-log_b{73}}{2}\)

Step-by-step explanation:

\(log_b{\sqrt{\frac{13}{73}}}\)

First we remove the square root

\(log_b({\frac{13}{73})^\frac{1}{2}}\)

As per log property we can move the exponent 1/2 before log

\(\frac{1}{2}log_b{\frac{13}{73}}\)

Now we apply log property to expand log (13/73)

log(a/b)= log(a) - log(b)

\(\frac{1}{2}log_b{13}-log_b{73}}\)

\(\frac{log_b{13}-log_b{73}}{2}\)


Related Questions