Answer:
The product of \(a^{4}(3a^{2}-2a+1)\) is \(3a^{6}-2a^{5}+a^{4}\) .
Step-by-step explanation:
As given the expression in the question be as follow .
\(= a^{4}(3a^{2}-2a+1)\)
First open the bracket
\(= a^{4}\times 3a^{2}-a^{4}\times 2a+a^{4}\times 1\)
Now by using the property of exponent .
\(x^{a}\times x^{b}= x^{a+b}\)
\(= 3a^{2+4}-2a^{4+1}+a^{4}\)
\(= 3a^{6}-2a^{5}+a^{4}\)
Therefore the product of \(a^{4}(3a^{2}-2a+1)\) is \(3a^{6}-2a^{5}+a^{4}\) .