Verified Answer :

a^4(3a^2 - 2a + 1)

= 3a^6 - 2a^5 + a^4

hope that helps

Answer:

The product of \(a^{4}(3a^{2}-2a+1)\) is \(3a^{6}-2a^{5}+a^{4}\) .

Step-by-step explanation:

As given the expression in the question be as follow .

\(= a^{4}(3a^{2}-2a+1)\)

First open the bracket

\(= a^{4}\times 3a^{2}-a^{4}\times 2a+a^{4}\times 1\)

Now by using the property of exponent .

\(x^{a}\times x^{b}= x^{a+b}\)

\(= 3a^{2+4}-2a^{4+1}+a^{4}\)

\(= 3a^{6}-2a^{5}+a^{4}\)

Therefore the product of \(a^{4}(3a^{2}-2a+1)\) is \(3a^{6}-2a^{5}+a^{4}\) .