Answered

line A: y=-1/2x+3

line B:y=2x+-4


what is the slop of line A                    ps: you might need to graph it


what is the slop of line B


what is the solution to this system of equations

Verified Answer :

Apocrophon
AFor the equation \(y=- \frac{1}{2}x+3\), the slope is \(- \frac{1}{2}\).
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if \(m=- \frac{1}{2}\), the slope is  \(- \frac{1}{2}\).

B) Since this equation is in the same form, you just find what m is equal to.
Since \(m=2\), that's the slope.

For the solution, set \(y=- \frac{1}{2}x+3\) equal to \(y=2x-4\), so it would be put together like this:
\(y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667\)
So your answer is -4.667.

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