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  • 08-01-2017
  • Physics
Answered

a bullet traveling at 5.0 X 10^2 meters per second is brought to rest by a 50 newton * second impulse. what is the mass of the bullet?

Verified Answer :

Anonymous Anonymous
  • 10-01-2017

As an equation this is: 
(F)(delta t) = (m)(delta v). 

You are given the impulse 
(F)(delta t) = 50 Ns 
You are given that the bullet goes from 500 m/s to 0 m/s, so delta v is 500 m/s. 

All you need to do is set up the equation: 
50 Ns = 500(m) m/s. 

Looks a lot like m = 0.1 kg

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