Answered

Solve the given equation over the interval [0, 2π): csc^2 x + 2 csc x = 0.

Verified Answer :

\(csc^2x+2cscx=0\)
Factor out the GCF which is csc x
\(cscx(cscx+2)=0\)
Set each factor equal to zero.
\(cscx=0\)  or \(cscx+2=0\)
Using the reciprocal sine function we can replace csc in the equations.
\(\frac{1}{sinx} =0\)  or \(\frac{1}{sinx} +2=0\)
The first equation yields 1 = 0 which is not true. However the second equation does offer 2 possible answers.
When solved for sinx you get 
\(sinx=- \frac{1}{2}\)
The sine function is negative in the 3rd and 4th quadrants.
You can use the unit circle or the 
\(sin^-^1\) feature on your calculator  \(sin^-^1(1/2)\)
\(210^o or 330^o\)  alter radian answer which is probably what you want is \(\frac{7 \pi }{6} or \frac{11 \pi }{6}\)