If we were to use the sine law we would get
sin(B) / b = sin(A) / a ----> sin(B) = bsin(A)/a = 13sin(35)/6 = 1.24275 to 5 d.p..,
so since this is greater than 1 there can be 0 triangles with these dimensions,
as the range of the sine function is [-1,1].
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